alex2wr

Now I get this: Failed allocation for 5 blocks, 60 bytes instead of the out of memory

The newest beta firmware is in the "Beta Firmware" forums.

Here's a direct link to Netduino 4.2 RC3 firmware:
http://forums.netdui...3-all-editions/

Chris

Done ... now I get this when deplying project


Error 3 'AnalogInput' is an ambiguous reference between 'Microsoft.SPOT.Hardware.AnalogInput' and 'SecretLabs.NETMF.Hardware.AnalogInput' C:\Users\Alex\Documents\Visual Studio 2010\Projects\baikulog\baikulog\main.cs 26 24 baikulog

and this one


Error 2 The type or namespace name 'InterruptPort' could not be found (are you missing a using directive or an assembly reference?) C:\Users\Alex\Documents\Visual Studio 2010\Projects\baikulog\baikulog\main.cs 25 24 baikulog

Hi alex2wr,

Have you tried upgrading to .NET MF 4.2 (RC3)? There was a bug in the garbage collector in .NET MF 4.1 which didn't quite clean up memory completely...and could cause OutOfMemoryExceptions when there was still plenty of RAM available. The newer build also frees up a bit more RAM for your application.

Chris

I'm running whatever came with the netduino plus, I beleive is 4.1. Where do I get 4.3?

Thanks,

Just about nothing you do on the GPS till have any effect on how it locks. You just need to make sure it's in an area with a clear view to the sky and it should pick up fix.

A solder jumper is a pair or 2 pads that can be shorted together with a small drop of solder. These can sometimes be used for configuration settings and such.

Hello Chris

Thank you for your feedback, I went ahead and tried to go out to an open area with and waited 45 minutes and still no lock.

Is it posible that the GPS is broken?

Alex,

I would also like to log a voltage in using the analog inputs, but I can't seem to make this work either.

I connected a 1.5v AA battery positive to GPIO_PIN_A0 and negative to ground and get random numbers. I also connected the 3.3v supply pin to GPIO_PIN_A0 and get the number 1023 and I'm not sure what this is.

Thanks,

Alex,

So I just read that 1023 is because the analog inputs are 10bit adc, 10^2 = 1024 - 1. So do I just interpolate? 0v = 0, 3.3v = 1023. If this is true, I just multiple the input value by 0.003.

Alex,