I have built a project which includes the following components:
Netduino Plus
Joystick + Board
Bluetooth
Accelerometer
My area is in software programming and thus I have no idea how many 9V batteries I need to power up these components together. Can somebody help me on this?
I would also appreciate if you tell me the method/formula used and what to look for.
Thank you!
Battery consumption
Started by xikky, Apr 30 2012 03:07 PM
5 replies to this topic
#1
Posted 30 April 2012 - 03:07 PM
#3
Posted 30 April 2012 - 04:06 PM
No, but I thought a 9V would be good. I'll look for LiPo batteries after work, thanks for mentioning. My main concern is that I'm afraid to burn the components. I may be talking gibberish now, but for a newbie like me on electronics .. that's the first thing that comes to mind.
I would be happy if the battery powers for 2hrs plus .. The point of the project is for software development knowledge so I don't need a high end battery but I just need the device to be powered during the project's display.
#4
Posted 01 May 2012 - 06:54 AM
Can someone tell me how to find the total Voltage and Amps to power up the above components together?
#5
Posted 01 May 2012 - 07:49 AM
Sorry Xikky, I've read your post yesterday, but I forgot to answer.
My guess is between 100 and 150 mA for the whole circuit. However, if you have a multimeter, the easiest way is measuring the (average) current.
Now, let's have a look at the capacity of some kind of 9V battery:
http://en.wikipedia....ne-volt_battery
For instance, an alkaline battery yields 565mAh, which stands for "565mA for hour". In other words that battery says "I am able to give you a continuous current of 565mA for one hour long, then I'll be over". But that's equivalent to "I am able to give you a continuous current of 56.5mA for ten hours long". So away...
Note that is mostly theoretical. Batteries are pretty complex. For instance, a battery can give you a peak of high current (e.g. 5 Amps), but immediately after there's an "hole" of energy. That's because most of the available charge is pulled out, and you must give time to the chemical reaction to restore a balance.
Okay, just for your info...
Finally...what do you mean as "total voltage"? Is it not 9V as the battery?
Cheers
My guess is between 100 and 150 mA for the whole circuit. However, if you have a multimeter, the easiest way is measuring the (average) current.
Now, let's have a look at the capacity of some kind of 9V battery:
http://en.wikipedia....ne-volt_battery
For instance, an alkaline battery yields 565mAh, which stands for "565mA for hour". In other words that battery says "I am able to give you a continuous current of 565mA for one hour long, then I'll be over". But that's equivalent to "I am able to give you a continuous current of 56.5mA for ten hours long". So away...
Note that is mostly theoretical. Batteries are pretty complex. For instance, a battery can give you a peak of high current (e.g. 5 Amps), but immediately after there's an "hole" of energy. That's because most of the available charge is pulled out, and you must give time to the chemical reaction to restore a balance.
Okay, just for your info...
Finally...what do you mean as "total voltage"? Is it not 9V as the battery?
Cheers
- xikky likes this
Biggest fault of Netduino? It runs by electricity.
#6
Posted 01 May 2012 - 08:00 AM
Thanks Mario Vernari your the best!
What I wanted to say with "total voltage" is if 9Volts is the right Voltage for the mentioned components.
.. again I'm sorry for my noobism xD!
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