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Battery consumption


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#1 xikky

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Posted 30 April 2012 - 03:07 PM

I have built a project which includes the following components:

Netduino Plus
Joystick + Board
Bluetooth
Accelerometer

My area is in software programming and thus I have no idea how many 9V batteries I need to power up these components together. Can somebody help me on this?

I would also appreciate if you tell me the method/formula used and what to look for.

Thank you!

#2 emg

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Posted 30 April 2012 - 03:17 PM

Does it have to be 9v cells? Have a look at some 'hobby' LiPo batteries used for quad-copters and such... Also, you never mentioned how long you need to power your device before replacement/recharge. Mins, Hours, Days?

#3 xikky

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Posted 30 April 2012 - 04:06 PM

No, but I thought a 9V would be good. I'll look for LiPo batteries after work, thanks for mentioning. My main concern is that I'm afraid to burn the components. I may be talking gibberish now, but for a newbie like me on electronics .. that's the first thing that comes to mind. I would be happy if the battery powers for 2hrs plus .. The point of the project is for software development knowledge so I don't need a high end battery but I just need the device to be powered during the project's display.

#4 xikky

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Posted 01 May 2012 - 06:54 AM

Can someone tell me how to find the total Voltage and Amps to power up the above components together?

#5 Mario Vernari

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Posted 01 May 2012 - 07:49 AM

Sorry Xikky, I've read your post yesterday, but I forgot to answer.

My guess is between 100 and 150 mA for the whole circuit. However, if you have a multimeter, the easiest way is measuring the (average) current.

Now, let's have a look at the capacity of some kind of 9V battery:
http://en.wikipedia....ne-volt_battery
For instance, an alkaline battery yields 565mAh, which stands for "565mA for hour". In other words that battery says "I am able to give you a continuous current of 565mA for one hour long, then I'll be over". But that's equivalent to "I am able to give you a continuous current of 56.5mA for ten hours long". So away...

Note that is mostly theoretical. Batteries are pretty complex. For instance, a battery can give you a peak of high current (e.g. 5 Amps), but immediately after there's an "hole" of energy. That's because most of the available charge is pulled out, and you must give time to the chemical reaction to restore a balance.
Okay, just for your info...

Finally...what do you mean as "total voltage"? Is it not 9V as the battery?

Cheers
Biggest fault of Netduino? It runs by electricity.

#6 xikky

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Posted 01 May 2012 - 08:00 AM

Thanks Mario Vernari your the best! :) What I wanted to say with "total voltage" is if 9Volts is the right Voltage for the mentioned components. .. again I'm sorry for my noobism xD!




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