I have a IRF510 Transistor, and I need to send 5V to the gate pin in order to open the circuit enough for the 12V signal to pass through. The problem is the Digital I/O's only send 3.3V. Do I need to purchase a second transistor to use with the Digital I/O to switch on the 5V to the IRF510? Or is there another method/transistor I could use to switch the 12V instead?
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#1
Posted 19 July 2014 - 02:44 PM
My doorbell sends me a text message and a push notification, does yours?
#2
Posted 22 July 2014 - 12:35 PM
What kind of load does the transistor switch? What is the current?
IRF510 can switch ~1A at VGS = 5V, but I am a little bit suspicious about that "...to open the circuit enough..."
You can use any general purpose/small signal BJT (2Nxxxx, BC5xx) or MOSFET (e.g. BS170) to control the power MOSFET. In special case (e.g. very fast switching) you might need a dedicated MOSFET driver IC.
IRL510 is the variant with lower gate threshold voltage (<2V), it can switch 1A at VGS > ~2.75V.
Also tagged with one or more of these keywords: Netduino Plus 2, IRF510, MOSFET
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